# Algebra 222 week 4 Test

п»їAlgebra 222 week 4 To discover

CLOSE WINDOWВ

Week 5: Quadratic Equations and Functions, Date Posted: 10/26/2014 1 ) Finding the root base of a quadratic equation with leading agent 1 Fix forВ

sumado a

.

=+y2в€’3y40

If there is more than one option, separate associated with commas. If there is no answer, click on " No answer. "

You answered correctly:

=yв€’В 4, you

2 . Locating the roots of a quadratic formula with leading coefficient greater than 1 Solve forВ

sixth is v

.

=2v2+3v2

If you have more than one answer, separate these commas. When there is no option, click on " No answer. "

You answered appropriately:

=vв€’В 2, -1/2

3. Completing the sq .

Fill in the blank to help make the expression aВ perfect square.

+в€’w26wВ

You clarified correctly:

+в€’w26wВ 9

2x2 -- 7x+1=0

You answered appropriately:

xВ =7+пѓ–41/4, 7-пѓ–/41/4

4. Making use of the quadratic formula: Specific answers

Employ theВ quadratic formulaВ to solve forВ

x

.

2x2-7x-1=0

You responded correctly:

xВ =7+пѓ–41/4, 7-пѓ–41/4

a few. Writing a quadratic formula given the roots as well as the leading coefficient Write theВ quadraticВ equation whoseВ rootsВ areВ

в€’1

andВ

3

, and in whose leadingВ coefficientВ isВ

a couple of

.

(Use the letterВ

back button

to represent theВ variable. )

The best answer can be:

2x2в€’4x-6=0

6. Discriminant of a quadratic formula

Compute the value of theВ discriminantВ and supply the number ofВ realВ solutions of theВ quadratic equation. =+в€’2x2в€’2x30

You solved correctly:

DiscriminantВ

=в€’20

Quantity of real solutionsВ

=0

several. Graphing a parabola from the form con = ax2

Graph theВ parabola.

=yв€’34x2

To graph the parabola, storyline theВ vertexВ and several additional details, two on each of your side from the vertex. After that click on the graph icon.

You answered:

The proper answer is: -2, zero, +2

back button

-2

-4

-6

-8

2

5

6

8

y

-2

-4

-6

-8

two

4

six

8

almost 8. Graphing a parabola with the form con = (x-a)2В + c

Chart theВ parabola.

=y++x125

To graph the parabola, plot the vertex and 4 additional factors, two to each side of the vertex. Then simply click on the chart icon.

The proper answer is usually: Y several -3, con 6вЂ”2, con -1 through 6 and up y7 times

-2

-4

-6

-8

2

four

6

almost 8

y

-2

-4

-6

-8

a couple of

4

six

8

being unfaithful. Solving a quadratic inequality written in factored contact form

Graph the answer to the followingВ inequalityВ on theВ number range. -11

0

1

a couple of

3

5

5

6

7

almost 8

9

10

11

10. Finding the optimum or minimum of a quadratic function

Solution the queries below about theВ quadraticВ function.

=gxв€’2x2в€’4x1

Does the function have a minimum or maximum value?

Lowest

Maximum

What is the function's minimum or perhaps maximum worth?

Where does the minimum or perhaps maximum benefit occur?

=x

You solved correctly:

Will the function have a minimum or maximum benefit?

Minimum

Maximum

What is the function's bare minimum or optimum value?

в€’3

Where does the minimum or maximum value occur?

=x1

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